Solve All Question For 50 Points.
Best And First Answer Will Be Marked As Brainlist.
Answers
Given :-
The age of Jacob will be three times that of his son.
Solution :-
Let the present age of Jacob be be x year
And the present Age of his son be be y year
Five years Ago
Jacob’s age will be = x + 5 year
Age of his son will be = y + 5 year
According to the Question,
⇒ x + 5 = 3(y + 5)
Adding 5 to both side,
⇒ x = 3y + 15 - 5
⇒ x = 3y + 10 … (i)
Five years ago,
Jacob’s age= x - 5 year
His son’s age = y - 5 year
Jacob’s age was seven times that of his son
⇒ x - 5 = 7(y - 5)
Putting the value of x from equation (i) we get
⇒ 3y + 10 - 5 = 7y - 35
⇒ 3y + 5 = 7y – 35
⇒ 3y - 7y = - 35 - 5
⇒ -4y = - 40
⇒ y = - 40/-4
⇒ y = 10 year
Putting the value of y in equation we get
⇒ x = 3 × 10 + 10
⇒ x = 40 years
Present age of Jacob = 40 years,
Present age of his son = 10 years.
x+y=14 .....(1)
x−y=4 ......(2)
On adding 1 and 2, we get,
2x=18
x=9
Putting this value in equation 2, we get,
9−y=4
y=5
Hence, x=9 and y=5.