Question

solve all question for class 10 ​

Answer 1

Answer:

$\frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1} = a - b \sqrt{3} \\ \frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1 } \times \frac{ \sqrt{3} - 1}{ \sqrt{3} - 1} = a - b \sqrt{ 3} \\ \frac{( \sqrt{3} - 1) {}^{2} }{( \sqrt{3} ) {}^{2} - 1 {}^{2} } = a - b \sqrt{3} \\ \frac{( \sqrt{3} ) {}^{2} + 1 {}^{2} - 2 \times \sqrt{3} \times 1}{3 - 1} = a - b \sqrt{3} \\ \frac{4 - 2 \sqrt{3} }{2} = a - b \sqrt{3} \\ \frac{4}{2} - \frac{2 \sqrt{3} }{2} = a - b \sqrt{3} \\ a = \frac{4}{2} = 2 \\ b = \frac{2}{2} = 1$

Answer 2

Answer:

Hey mate your answer is given below