Math, asked by aninditadas711, 4 months ago

Solve all the problems.​

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Answered by saniyaray630
1

1. Length of first jump=3/5 m

Length of second jump=3/4 m

Length of third jump =7/10 m

Therefore, total jump=⅗+¾+⁷/¹⁰

=12+15+14/20

=41/20 m

=2¹/20 m

2. Time for table=2¾

Time for chair=1⅓

Total time taken =2¾+1⅓

=15/4+4/3

= 45+16/3

=61/3 hrs

=20⅓ hrs

3. Total quantity of vegetables of = 4½+3¼+¾+1⅛

=9/2+13/4+3/4+9/8

= 36+26+6+9/8

=77/8 kg

= 9⅝ kg

4. Remaining piece of cloth =7¼-3⅘

=29/4-19/5

=69/20

=3 9/20

5. Gas left inside the cylinder = 35-23⅗

=35-118/5

=175-118/5

=57/5 li

= 11⅖ li

6. Weight of the rice=40⅙-13¾

=241/6-55/4

=482-165/12

= 317/12

=26 5/12 kg

Answered by ItzDazzingBoy
2

Answer:

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