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Soln 27) 4 × 4 + 4 × 2
= 16 + 8
= 24
............................................................
Soln 28) Let the supplementary angles be 4x and 5x respectively.
A/q,
4x + 5x = 180°
=> 9x = 180°
=> x = 180°/9
=> x = 20°
Required angles
4x = 4 × 20° = 80°
and 5x = 5 × 20° = 100°
•°• Difference = 100° - 80°
= 20°
...............................................................
Soln 29) y/7 = 45/5
=> 5 × y = 45 × 7
=> 5y = 45 × 7
=> y = (45 × 7)/5
=> y = 9 × 7
=> y = 63
.....................................................................
Soln 30) Let the length be 4x m and the breadth be 3x m.
Perimeter of the rectangle = 140 m
=> 2(l + b) = 140
=> 2(4x + 3x) = 140
=> 2 × 7x = 140
=> 14x = 140
=> x = 140/14
=> x = 10
•°• Length = 4x = 4 × 10 = 40 m
and breadth = 3x = 3 × 10 = 30 m
•°• Area of the rectangle
= length × breadth
= (40 × 30) m²
= 1200 m²
........................................................................
Soln 31) •°• The value of (y - x)
= 9 × ( 8 × 7 ) - ( 9 × 8 ) × 7
= ( 9 × 56 ) - ( 72 × 7 )
= 504 - 504
= 0
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Answer:
Step-by-step explanations
[ (12÷3) ×4 +4 ×2]
[4×4+4×2]
16+8
=24
Let the angle of supplementary are4x and 5x
As we know that the sum of supplementary angle is 180
4x+5x=180
9x =180
X=20
First angle be=4×20
=80
Second angle be = 5×20
=100
Their difference angle be =first angle - second angle
100-80=
20
Y:7: : 45:5
By the cross multiple
5y=315
Y=315/5
Y=63
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