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Answer:
1. Area of photograph = l× b=4cm×3.5cm=14cm²
2.Area of stamp= side²=(2.5)²=6.25 cm²
3. Area of room= l×b=5.5×3.5=19.25 m²
4.perimeter of park=4×side=4×100=400 m
area of park=side²=(100)²=10000m²
Answer:
1) Area of the photo graph = 1×b=4cm×3.5cm=14cm^2
1) Area of the photo graph = 1×b=4cm×3.5cm=14cm^22) area of stamp = side^2 =(2.5)^×=6.25cm^2
1) Area of the photo graph = 1×b=4cm×3.5cm=14cm^22) area of stamp = side^2 =(2.5)^×=6.25cm^23) area of room = l×b = 5.5 x 3.5 =19.25m^2
1) Area of the photo graph = 1×b=4cm×3.5cm=14cm^22) area of stamp = side^2 =(2.5)^×=6.25cm^23) area of room = l×b = 5.5 x 3.5 =19.25m^24) perimetef of park=4× side=4×100m
1) Area of the photo graph = 1×b=4cm×3.5cm=14cm^22) area of stamp = side^2 =(2.5)^×=6.25cm^23) area of room = l×b = 5.5 x 3.5 =19.25m^24) perimetef of park=4× side=4×100m are of park side =(100)^2 = 10000m^2.
1) Area of the photo graph = 1×b=4cm×3.5cm=14cm^22) area of stamp = side^2 =(2.5)^×=6.25cm^23) area of room = l×b = 5.5 x 3.5 =19.25m^24) perimetef of park=4× side=4×100m are of park side =(100)^2 = 10000m^2.hope this helps.....
1) Area of the photo graph = 1×b=4cm×3.5cm=14cm^22) area of stamp = side^2 =(2.5)^×=6.25cm^23) area of room = l×b = 5.5 x 3.5 =19.25m^24) perimetef of park=4× side=4×100m are of park side =(100)^2 = 10000m^2.hope this helps.....plz mark me as brainliest answer...