Math, asked by ayushmalik28, 9 months ago

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Answered by neelam13kapoor
1

Answer:

1)The two no.s are 43 and 15

2)The two no.s are 27 and 29

3)The multiples of 7 are 252, 259, 266

4) He traveled 20 km by train

Step-by-step explanation:

Let greater no be x and other no. be y

    x+y=58

 + x-y=28

__________

   2x  = 86

   x    = 86/2

  x     = 43

x+y = 58

43+y = 58

y  = 58-43

y = 15

2) Let smaller no. be x

   So, other no will be x+2

   Hence, x+x+2=56

               2x      = 56-2

               x         =54/2

               x        = 27

Hence, the two no.s are 27(x) and 29 (x+2)

3) Let the multiples of 7 be x, x+7, x+14

Hence, x+x+7+x+14=777

           3x+21          =777

           3x= 777-21

           3x=756

           x=756/3

           x=252

Hence the multiples of 7 are 252(x), 259(x+7), 266(x+14)

4) Let the distance traveled by train be x km

   so, distance traveled by bus will be (2x) km

  Hence, total distance = 10km + x+2x

 70 km = 10 +3x

 70-10 =3x

60/3 =x

20 km = x

Hence, he traveled 20 km by train

Answered by Anonymous
2

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