solve all the three parts A, B and C
write step by step answer of all the three parts
wrong answers will be reported
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30
Question :-
Find the probability of a family chosen at random having
a) at least one girl
b) 2 girls
c) at most 1 girl
Answer -
a) In at least one girl, the families having one girl as well as families having 2 girls will be included -
So, Possible outcomes = Families having 1 girl + Families having 2 girls
= 814 + 475
= 1289
Total outcomes = 475 + 814 + 211
= 1500
Probability = 1289 / 1500
Probability of getting atleast one girl = 1289 / 1500
b) Families having 2 girls = 475
Total families = 1500
Probability of getting 2 girls = 475 / 1500 = 19 / 60
c) At most includes families with one girl as well as families having no girl.
Possible outcomes = 814 + 211 = 1025
Total families = 1500
Probability = 1025 / 1500 = 41 / 60
Probability of getting at most 1 girl = 41 / 60
Answered by
1
Answer:
1289/1500
19/60
41/60
Step-by-step explanation:
hope it helps!
Happy holi dahan to you and your family!!
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