Math, asked by Anonymous, 1 year ago

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Answered by divprsw16
1

18:-cos35°/sin55° +sin11°/cos79° -cos28°cosec62°

=cos(90-55)/sin55° +sin(90-79)/cos79°-cos28°/sin62°

=sin55°/sin55° +cos79°/cos79° -cos(90-62)/sin62°

=1+1-sin62°/sin62°

=1+1-1. =1


divprsw16: 16:- sin35°sin55°-cos35°cos55°. Here, A=35° and B=55°. So, it's in the form of:- sinAsinB-cosAcosB. This is in the form of -cos(A+B)=-cos(35°+55°). =-cos90°. =-0. =0
divprsw16: Sorry this' the 17th number
divprsw16: 16:- tan7°tan23°tan60°tan67°tan83°. tan7°tan23°tan60°tan(90-23)tan(90-7). =tan7°tan23°tan60°cot23°cot7°. =tan7°cot7°tan23°cot23°tan60° =1.1.tan60°. =√3
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