Question

solve all this... of Factorisation​

Answer 1

Step-by-step explanation:

$1. {x}^{2} - {y}^{2} - 2y - 1 \\ \: \: {x}^{2} - ( {y}^{2} + 2y + 1) \\ {x }^{2} - {(y + 1)}^{2}$

$3. {x}^{2} {y}^{2} - {x}^{2} - {y}^{2} + 1 \\ \\ {x}^{2} {y}^{2} - {x}^{2} - {y}^{2} + 1 - 2xy + 2xy \\ {(xy + 1)}^{2} - {(x + y)}^{2}$

$5. \: \: 5 - 4x - 12 {x}^{2} \\ - (12 {x}^{2} + 4x - 5) \\ - (12 {x}^{2} + 10x - 6x - 5) \\ - (2x(6x + 5) - 1(6x + 5)) \\ - (2x - 1)(6x + 5)$