Solve and 2x + 3y = 11 and 2x - 4y= -24 and hence find the value of ‘m’ for which y = mx +3
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Answer:
Lets reform the equation in its standard form of y=mx+c
2x+3y=6
y=−2x/3+2
Slope=−2/3,y−intercept=2
Only line with y-intercept=2 is (IV)
And it has negative slope too.
Hence, IV represents graph of 2x+3y=6.
Step-by-step explanation:
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3x+y=-1......eqn 1
-2x+3y=19.....eqn 2
multiplying eqn 1 by 3 in order to eliminate y
9x+3y=-3.......eqn3
subtracting eqn 3 frm 2
-2x+3y=19
9x+3y=-3
(- ) - - +
-11x =22
x =22/-11
x = -2
substituting x= -2 in eqn1
we get y= 5
now,
y=mx+3
5=m(-2)=3
5= -2m+3
5-3= -2m
2= -2m
-2/2=m
-1=m
therefore m= -1
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