solve and answer maths
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radius of circle =13cm.
chord =10cm.
distance of the chord from the centre =?
IN ΔABC.
AC²=AB²+BC²....(by using Pythagoras theorem)
13²=10²+BC²
169=100+BC²
BC²=169-100
BC²=69
BC=√69.
. °. BC=√69.
distance of the chord from the centre =√69cm.
.°. option C is the correct answer.
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