Question

solve and check 3y+2 (y+2) = 13- (2y-5)​

Answer 1

Answer:

Reorder the terms:

3y + 2(2 + y) = 13 + -1(2y + -5)

3y + (2 * 2 + y * 2) = 13 + -1(2y + -5)

3y + (4 + 2y) = 13 + -1(2y + -5)

Reorder the terms:

4 + 3y + 2y = 13 + -1(2y + -5)

Combine like terms: 3y + 2y = 5y

4 + 5y = 13 + -1(2y + -5)

Reorder the terms:

4 + 5y = 13 + -1(-5 + 2y)

4 + 5y = 13 + (-5 * -1 + 2y * -1)

4 + 5y = 13 + (5 + -2y)

Combine like terms: 13 + 5 = 18

4 + 5y = 18 + -2y

Solving

4 + 5y = 18 + -2y

Answer 2

Answer:

• The value of y is 2.

Step-by-step explanation:

Given,

• $\tt 3y + 2(y + 2) = 13 - (2y - 5)$

To Find,

• The value of y. (Solve and check)

Solution,

$:\implies \tt 3y + 2(y + 2) = 13 - (2y - 5) \\ \\ :\implies \tt 3y + 2y + 4 = 13 - 2y + 5 \\ \\ :\implies \tt 5y + 4 = 18 - 2y \\ \\ :\implies \tt 5y + 2y = 18 - 4 \\ \\ :\implies \tt 7y = 14 \\ \\ :\implies \color{red} \boxed{ \tt y = 2}$

Verification,

$:\implies \tt 3y + 2(y + 2) = 13 - (2y - 5) \\ \\ :\implies \tt 3(2) + 2(2 + 2) = 13 - (2(2) - 5) \\ \\ :\implies \tt 6 + 2(4) = 13 - (4 - 5) \\ \\ :\implies \tt 6 + 8 = 13 - ( - 1) \\ \\ :\implies \tt 14 = 13 + 1 \\ \\ :\implies \tt 14 = 14 \\ \\ :\implies \tt LHS = RHS$

Required Answer,

• The value of y is 2.