Math, asked by harjinderpalsingh864, 5 hours ago

Solve and check
4x-1/3=1/5+3x

CLASS 7​

Answers

Answered by Anonymous
1

Answer:

x=8/15

refer the above attachment

Attachments:
Answered by MasterDhruva
14

Solution :-

We have two different methods to solve this equation. The given equation consists of two same variables x. We'll solve both the methods here. The given equation is,

\sf \leadsto 4x - \dfrac{1}{3} = \dfrac{1}{5} + 3x

The first method is as follows,

\sf \leadsto 4x - \dfrac{1}{3} = \dfrac{1}{5} + 3x

\sf \leadsto 4x - 3x = \dfrac{1}{5} + \dfrac{1}{3}

\sf \leadsto 1x = \dfrac{3 + 5}{15}

\sf \leadsto 1x = \dfrac{8}{15}

\sf \leadsto x = \dfrac{\dfrac{8}{15}}{1}

\sf \leadsto x = \dfrac{8}{15}

The second method is as follows,

\sf \leadsto 4x - \dfrac{1}{3} = \dfrac{1}{5} + 3x

\sf \leadsto \dfrac{12x - 1}{3} = \dfrac{1 + 15x}{5}

\sf \leadsto 5(12x - 1) = 3(1 + 15x)

\sf \leadsto 60x - 5 = 3 + 45x

\sf \leadsto 60x - 45x = 3 + 5

\sf \leadsto 15x = 8

\sf \leadsto x = \dfrac{8}{15}

Therefore, the value of x is 8/15.

\:

Now, let's check our answer.

\sf \leadsto 4x - \dfrac{1}{3} = \dfrac{1}{5} + 3x

\sf \leadsto 4 \bigg( \dfrac{8}{15} \bigg) - \dfrac{1}{3} = \dfrac{1}{5} + 3 \bigg( \dfrac{8}{15} \bigg)

\sf \leadsto \dfrac{32}{15} - \dfrac{1}{3} = \dfrac{1}{5} + \dfrac{24}{15}

\sf \leadsto \dfrac{32 - 5}{15} = \dfrac{3 + 24}{15}

\sf \leadsto \dfrac{27}{15} = \dfrac{27}{15}

Hence, verified !!

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