Question

Solve and check 9x +3 = 3(x-1)+6

Answer 1

Answer:

$9x + 3 = 3(x - 1) + 6 \\ \\ = > 9x + 3 = 3x - 3 + 6 \\ \\ = > 9x + 3 = 3x + 3 \\ \\ = > 9x - 3x = 3 - 3 \\ \\ = > 6x = 0 \\ \\ = > x = \frac{0}{6} \\ \\ = > x = 0 \\ \\ so \: \: verifying \: my \: answer \\ \\ 9(0) + 3 = 3(0 - 1) + 6 \\ \\ = > 0 + 3 = 3( - 1) + 6 \\ \\ = > 3 = - 3 + 6 \\ \\ = > 3 = 3 \\ \\ hence \: verified$

✏ so x = 0

hope it helps uH :)

Answer 2

Answer:

=> The value of x is 0 and it satisfies the given equation.

Step-by-step explanation:

Given that:-

$9x +3 = 3(x-1)+6$

To find:- The value of the x,

By using the method of transposition,

As we have,

=> $9x +3 = 3(x-1)+6$

First of all, distribute the terms:

=> $9x +3 = 3x-3+6$

Add the numbers,

=> $9x +3 = 3x+3$

Subtract $3$ from both sides,

=> $9x +3 -3= 3x+3-3$

Simplifying it further,

=> $9x = 3x$

Subtract $3x$ from both sides,

=> $9x-3x = 3x-3x$

=> $6x=0$

Divide both sides by $6$,

=> $x = 0$

So, the value of x is 0.

For checking, plug the value of x as $0$:

=> $9x +3 = 3(x-1)+6$

=> $9(0) +3 = 3(0-1)+6$

=> 0 + 3 = 3 ( -1 ) + 6

Simplifying it further,

=> 3 = ( -3 ) + 6

=> 3 = 3

LHS = RHS