solve and check
a) m-(m-1) / 2 = 1 - (m-2)/ 3
b) 8(2x-5 ) - 6 ( 3x - 7 ) =1
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Answer:
a) Given, m - (m - 1)/2 = 1 - (m - 2)/3
Multiply both sides by the LCM of the denominators to get rid of fractional denominator.
Now transpose variables to one side and constants to another side to form a linear equation.
m - (m - 1)/2 = 1 - (m - 2)/3
LCM of the denominators is 6
Multiply the LCM on both sides
⇒ 6[m - (m - 1)/2] = 6[1 - (m - 2)/3]
⇒ 6m - 3m + 3 = 6 - 2m + 4
⇒ 5m = 7
Hence,m = 7/5
b) Given:
8(2x-5)-6(3x-7)=1
16x -40-18x+42 = 1
-2x+2 = 1
-2x = -1
x = 1/2.
Therefore, the value of x is 1/2.
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