Math, asked by rupalikumari748834, 8 months ago

solve and check it.8-5(3-2n)=n-4( n+9) .​

Answers

Answered by samirattar2004
0

Step-by-step explanation:

8(3-2n)-5(3-2n)=n(n+9)-4(n+9)

8(3-2n)-5(3-2n)=n(n+9)-4(n+9)24-16n-15+10n=n^+9n-4n-36

8(3-2n)-5(3-2n)=n(n+9)-4(n+9)24-16n-15+10n=n^+9n-4n-369-6n=n^+5n-36

8(3-2n)-5(3-2n)=n(n+9)-4(n+9)24-16n-15+10n=n^+9n-4n-369-6n=n^+5n-369+36=n^+5n+6n

8(3-2n)-5(3-2n)=n(n+9)-4(n+9)24-16n-15+10n=n^+9n-4n-369-6n=n^+5n-369+36=n^+5n+6n42=n^+11n

8(3-2n)-5(3-2n)=n(n+9)-4(n+9)24-16n-15+10n=n^+9n-4n-369-6n=n^+5n-369+36=n^+5n+6n42=n^+11n=n^+11n-42

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