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Area of square-Area of 4 quadrants
1st :
area of square , side=12
then area =a^2=(12)^2
therefore area of square= 144cm^2----1
2nd :
area of quadrant: 1/4πr^2
1/4×22/7×6×6
198/7×4. [ given 4 quadrants]
so, 792/7= 113.1 cm^2----------2
Subtracting the two area so that we get the required shaded region
144-113.1
=30.9 cm^2
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Answer:
Given,
side of square = 12 cm(AB = BC = CD = DA)
and, AP = PB = BQ =QC= CR = RD = DS = AS =(1/2× AB)= 6cm
Now,
Area of shaded region = area of square - 4× area of quadrants
=>Area of shaded region = (side)² - 4×(1/4 × r²)
=>Area of shaded region = (12)² - ( 3.14 × 6 × 6)
=>Area of shaded region = 144 - 113.04
=> Area of shaded region = 30.96 cm²
thanks
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