Question

solve and explain!!






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Answer 1

Answer:

ઓઐટોૠવૉતફફધથટબટધછ

Step-by-step explanation:

ઑૠઑટૃ

Answer 2

$\Huge{\textbf{\textsf{{\purple{Ans}}{\pink{wer}}{\color{pink}{:}}}}}$

$x - \frac{1}{x} = 3 \\ \implies \: \frac{ {x}^{2} - 1 }{x} = 3 \\ \implies \: {x}^{2} - 1 = 3x \\ \implies \: {x}^{2} - 3x - 1 = 0 \\ \\ x = \frac{ - ( - 3) \pm \sqrt{ {( - 3)}^{2} - 4 \times 1 \times ( - 1)} }{2 \times 1} \\ \: \: \: = \frac{3 \pm \sqrt{9 + 4} }{2} \\ \: \: \: = \frac{ 3 \pm \sqrt{13} }{2} \\ \\ \therefore \: x_1 = \frac{3 + \sqrt{13} }{2} \\ \\ x_2 = \frac{3 - \sqrt{13} }{2}$

Formula :

$the \: roots \: of \: the \: following \: eqution \: is \: \\ a {x}^{2} + bx + c = 0 \\ \\ \underbrace {x }_{x_ 1 \: \: and \: \: x_ 2} = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$