solve and explain plz
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Construction: CE
When Area = 4 sq cm
=> Side^2 = Area
=> Side = 2 cm
Thus, AD = 2 cm
AE = 2/2 = 1 cm [median]
Area of triangle ADE = 1/2 × bh = 1/2 × 2 × 1 = 1 sq cm
Similarly, Area of triangle EBC is also 1 sq cm
Area of triangle EDC = 4 - 1 - 1 = 2 sq cm
Area of FCD = 1/2 × Area of triangle EDC
Area of GDC = 1/2 × Area of triangle FCD
Area of HCD = 1/2 × Area of triangle GDC
Area of KDC = 1/2 × Area of triangle HCD
Thus, Area of KDC = 1/2 × 1/2 × 1/2 × 1/2 × 2 = 1/8 sq cm
Property used: The median divides the triangle into two parts of equal area.
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