solve and explain this clearly
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We have,
Length of the metal wire, I = 1 m
Diameter of the wire, d = 0.3 mm
Radius, r = 0.3/2 mm = 0.15 mm = 0.15 x 10-³ m R
Resistance of the metal, R = 26 Q
Thus,
Resistivity, p = RA/L
= R X Tr L 26 x 3.14 x (0.15 x 10-3)²/1 = Qm
= 1.84 x 10° Qm.
The resistivity of the metal at 20°C is 1.84 x 10-80 m.
From the table given below, we can say that the material under consideration is Manganese.
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yes bruh.. i am also in 10th(•‿•)
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