Question

solve and factorise 75(2x-10)/8(x^2-10x)

please fast it's urgent..

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Answer 1

we have to factories:-

$\begin{gathered} \sf \: \dfrac{75(2x - 10)}{8( {x}^{2} - 10x) } = 1 \\ \\ \\ \implies \sf \: 150x - 750 = 8 {x}^{2} - 80x \\ \\ \\ \implies \sf \:0 = 8 {x}^{2} - 80x - 150x + 750 \\ \\ \\ \implies \sf \:0 = 8 {x}^{2} - 230x + 750 \\ \\ \\ \implies \sf \:0 = 2(4 {x}^{2} - 115x + 375) \\ \\ \\ \implies \sf \:4 {x}^{2} - 115x + 375 = 0 \\ \\ \\ \implies \sf \:4 {x}^{2} - 100x - 15x + 375 = 0 \\ \\ \\ \implies \sf \:4x( {x} - 25) - 15(x - 25) = 0 \\ \\ \\ \implies \boxed{\sf \:(x - 25)(4x - 15) = 0}\end{gathered}$

thanks!!