Math, asked by vasanthakshayaraaj, 22 hours ago

Solve and find out all of its possible values :
(k ^ 2 + 3 ^ 2) = 5​

Answers

Answered by rajunaga110
0

Step-by-step explanation:

if k is a real number then there is no such number that satisfies the given equation

so it is possible if it is a imaginary number

so k^2+9=5

k^2=5-9= -4

k= 2√-1

so k= 2i

Answered by amitnrw
0

Given :

k² + 3²   = 5

To Find :  possible values  of k

Solution:

k² + 3²   = 5

=> k² + 9 = 5

=> k² = - 4

Square of a real number can not be negative

Hence no real value of k is possible

if Question is

k² + 3²   = 5²

=> k² + 9 = 25

=> k² = 16

=> k = ±4

Possible values of k are 4 and - 4

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