Solve and find out all of its possible values :
(k ^ 2 + 3 ^ 2) = 5
Answers
Answered by
0
Step-by-step explanation:
if k is a real number then there is no such number that satisfies the given equation
so it is possible if it is a imaginary number
so k^2+9=5
k^2=5-9= -4
k= 2√-1
so k= 2i
Answered by
0
Given :
k² + 3² = 5
To Find : possible values of k
Solution:
k² + 3² = 5
=> k² + 9 = 5
=> k² = - 4
Square of a real number can not be negative
Hence no real value of k is possible
if Question is
k² + 3² = 5²
=> k² + 9 = 25
=> k² = 16
=> k = ±4
Possible values of k are 4 and - 4
Learn More:
Solve the following x+y/xy=5 and x-5/xy=7 - Brainly.in
brainly.in/question/8168066
solve for x and y : x+y/xy=2,xy/=6
brainly.in/question/12892518
Similar questions