Question

Solve and Find..the solution

Answer 1

${p}^{2} {x}^{2} + ( {p}^{2} - {q}^{2} )x - {q}^{2} = 0 \\ {p}^{2} {x}^{2} + {p}^{2}x - {q}^{2} x - {q}^{2} = 0 \\ {p}^{2} x(x + 1) - {q}^{2} (x + 1) = 0 \\ (x + 1)( {p}^{2} x - {q}^{2}) = 0 \\ x + 1 = 0 \: or \: {p}^{2} x \: - {q}^{2} = 0 \\ x = - 1 \: \: or \: \: {p}^{2} x = {q}^{2} \\ x = - 1 \: \: or \: \: x \: = \frac{ {q}^{2} }{ {p}^{2} }$
Hope this help.........