solve and find the value of k for which the pair of linear equatioms kx+y=k2 and x+ky=1 have infinitely many solutions
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The equation as infinitely many solution
Therefore a1 / a2 =k/1
b1/ b2 = 1/k
c1/c2 =K2/1
Here a1/a2=b1/b2=c1/c2
Therefore k/1 =1/k =k2/1
Therefore k square =1square
Therefore k=1 .
Therefore a1 / a2 =k/1
b1/ b2 = 1/k
c1/c2 =K2/1
Here a1/a2=b1/b2=c1/c2
Therefore k/1 =1/k =k2/1
Therefore k square =1square
Therefore k=1 .
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