solve and get point
if the sum of zeroes of quadratic
kx² +4x+7k is equal to the product find the value of k
Answers
Compare given Quadratic polynomial kx²+2x+3k by
ax²+bx+c , we get
a = k , b = 2 , c = 3k
\begin{gathered}i ) Sum \:of \:the \:zeroes = \frac{-b}{a}\\=\frac{-2}{k}--(1)\end{gathered}i)Sumofthezeroes=a−b=k−2−−(1)
\begin{gathered}ii) Product \:of \: the \: zeroes = \frac{c}{a}\\=\frac{3k}{k}\\=3--(2)\end{gathered}ii)Productofthezeroes=ac=k3k=3−−(2)
According to the problem given,
sum of the zeroes is equal to their product.
[tex]\frac{-2}{k}=3k−2=3
[tex]\implies -2=3k⟹−2=3k
\implies \frac{-2}{3}=k⟹3−2=k
Therefore,
value \: of \: k = \frac{-2}{3}valueofk=3−2
Answer:
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