Question

solve and given the positive value of x which satisfies the given equations: (2x+4)^2-(x-5)^2= 26x

Answer 1

Hey mate.. I hope this is the answer...


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Answer 2

The solution of equation is $\sqrt{3},-\sqrt{3}$.

Step-by-step explanation:

Given : Equation $(2x+4)^2-(x-5)^2= 26x$

To find : Solve and given the positive value of x which satisfies the given equations ?

Solution :

$(2x+4)^2-(x-5)^2= 26x$

Using algebraic identity, $(a\pm b)=a^2+b^2\pm 2ab$

$4x^2+16+16x-(x^2+25-10x)= 26x$

$4x^2+16+16x-x^2-25+10x= 26x$

$3x^2+26x-9= 26x$

$3x^2=9$

$x^2=\frac{9}{3}$

$x^2=3$

$x=\pm\sqrt{3}$

Therefore, the solution of equation is $\sqrt{3},-\sqrt{3}$.

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