solve and verify
5(x-1)+2(x+3)+6=0
Answers
Answered by
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5(x-1)+2(x+3)+6=0
5x-5+2×+6+6 = 0
7x+12-5 = 0
7x+7 = 0
transposing 7 from LHS to RHS
7x = 0+7
7x = 7
x = 7÷7 = 1
Verification
LHS RHS
(JUST KEEP 1 IN THE PLACE OF x) 0
(both lhs and rhs should be equal)
Answered by
0
Answer:
in 1st step multiply 5 with x and -1 then again multiply 2 with x and 3 and then solve it as I said at first after multiplying answer will come 5x - 5 + 2x+6+6 and in 3rd step the answer will come 5x+2x-5+6+6 and from here do it sweetie do in algebraic expression
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