Question

solve and verify
5(x-1)+2(x+3)+6=0

Answer 1

5(x-1)+2(x+3)+6=0

5x-5+2×+6+6 = 0

7x+12-5 = 0

7x+7 = 0

transposing 7 from LHS to RHS

7x = 0+7

7x = 7

x = 7÷7 = 1

Verification

LHS RHS

(JUST KEEP 1 IN THE PLACE OF x) 0

(both lhs and rhs should be equal)

Answer 2

Answer:

in 1st step multiply 5 with x and -1 then again multiply 2 with x and 3 and then solve it as I said at first after multiplying answer will come 5x - 5 + 2x+6+6 and in 3rd step the answer will come 5x+2x-5+6+6 and from here do it sweetie do in algebraic expression