Math, asked by AvMonster, 3 months ago

Solve and verify: 5(x-1)+2(x+3)+6=0

Answers

Answered by itzwhitedevil
1

Answer:

\huge\bold{\color{orange}{\underline{\color{olive}{\underline{\red {a}\pink {n}\color{gold}{s}\color{silver}{w}\color{aqua}{e}\color{yellow}{r}}}}}}

5(x - 1) + 2(x + 3) + 6 = 0 \\   \longrightarrow \: 5x - 5 + 2x + 6 + 6 = 0 \\  \longrightarrow \: 7x + 7= 0 \\  \longrightarrow \: x =  \frac{ - 7}{7}  =  - 1

Answered by matangidevi198597
1

Answer:</strong></p><p></p><p><strong>[tex]Answer:\huge\bold{\color{orange}{\underline{\color{olive}{\underline{\red {a}\pink {n}\color{gold}{s}\color{silver}{w}\color{aqua}{e}\color{yellow}{r}}}}}}answer</strong></p><p></p><p><strong>[tex]Answer:\huge\bold{\color{orange}{\underline{\color{olive}{\underline{\red {a}\pink {n}\color{gold}{s}\color{silver}{w}\color{aqua}{e}\color{yellow}{r}}}}}}answer\begin{gathered}5(x - 1) + 2(x + 3) + 6 = 0 \\ \longrightarrow \: 5x - 5 + 2x + 6 + 6 = 0 \\ \longrightarrow \: 7x + 7= 0 \\ \longrightarrow \: x = \frac{ - 7}{7} = - 1\end{gathered}5(x−1)+2(x+3)+6=0⟶5x−5+2x+6+6=0⟶7x+7=0⟶x=7−7=−1</strong></p><p></p><p><strong>[tex]Answer:\huge\bold{\color{orange}{\underline{\color{olive}{\underline{\red {a}\pink {n}\color{gold}{s}\color{silver}{w}\color{aqua}{e}\color{yellow}{r}}}}}}answer\begin{gathered}5(x - 1) + 2(x + 3) + 6 = 0 \\ \longrightarrow \: 5x - 5 + 2x + 6 + 6 = 0 \\ \longrightarrow \: 7x + 7= 0 \\ \longrightarrow \: x = \frac{ - 7}{7} = - 1\end{gathered}5(x−1)+2(x+3)+6=0⟶5x−5+2x+6+6=0⟶7x+7=0⟶x=7−7=−1

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