Question

solve and verify
x-2/6x+1 = 1​

Answer 1

Equation given :

$\dashrightarrow\sf\dfrac{x-2}{6x+1}=1$

Solution :

$\longmapsto\sf\dfrac{x-2}{6x+1}=1$

$\longmapsto\sf{x-2=1(6x+1)}$

$\longmapsto\sf{x-2=6x+1}$

$\longmapsto\sf{x-6x=1+2}$

$\longmapsto\sf{-5x=3}$

$\longmapsto\sf{-x=}\dfrac{3}{5}$

$\longmapsto\sf{x=}{-}\dfrac{3}{5}$

${\boxed{\sf{\green{Verification \ :}}}}$

Equation given :

$\to\sf\dfrac{x-2}{6x+1}=1$

Putting the value of “x”.

$\leadsto\sf{\dfrac{\dfrac{-3}{5} - 2}{6\times \dfrac{-3}{5} + 1} = 1}$

$\leadsto\sf{\dfrac{\dfrac{-3-10}{5}}{ \dfrac{-18}{5} + 1} = 1}$

$\leadsto\sf{\dfrac{\dfrac{-13}{5}}{ \dfrac{-18+5}{5}} = 1}$

$\leadsto\sf{\dfrac{\dfrac{-13}{5}}{ \dfrac{-13}{5}} = 1}$

$\leadsto\sf{\dfrac{-13}{5}}{=}1(\dfrac{-13}{5})$

$\sf\blue{(By \ cross \ multiplication )}$

$\leadsto\sf{\dfrac{-13}{5}}{=}\dfrac{-13}{5}$

$\underline{\rm{\pink{Hence, L.H.S. = R.H.S.}}}$

$\underline{\rm{\pink{Thus, Verified}}}$