Solve any difficult probability question
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noddyrishav:
please solve 15 and 16 problems
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(1) P(get a red)= total red balls/total no of balls
= 3/9
= 1/3
(2) P(non red)= total non red balls/total balls
= 6/9
= 2/3
(3) P(either red or white)= total no of red or white balls/total no of balls
= 3/9
= 1/3
= 3/9
= 1/3
(2) P(non red)= total non red balls/total balls
= 6/9
= 2/3
(3) P(either red or white)= total no of red or white balls/total no of balls
= 3/9
= 1/3
please solve 15 or 16 one problem
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