Question

Solve any one of them
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Answer 1

Answer:

$\int _0^1e^ti+e^{-2t}j+tkdt=\frac{-j+e^2\left(j+k\right)}{2e^2}+i\left(-1+e\right)$

Step-by-step explanation:

$=\int _0^1e^tidt+\int _0^1e^{-2t}jdt+\int _0^1tkdt$

$=\int\limits^1_0 {e^tidt} =i(e-1)$

$=\int\limits^1_0 {e^-^2^tjdt}=\frac{e^2-1}{2e^2} j$

$=\int\limits^1_0 {tkdt}=k\frac{1}{2}$

$=i(e-1)+\frac{e^2-1}{2e^2} j+k\frac{1}{2}$

$\frac{e^2(j+k)-j}{2e^2} +(e-1)i$ in a composite image:

$i(e-1)+\frac{e^2-1}{2e^2} j+k\frac{1}{2}$

$=\frac{-j+e^2(j+k)}{2e^2} +i(-1+e)$

Answer 2

Answer:

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