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Answer:
2).ta= 5
su= 12
tu= 13
sin t= 12/13
cos t = 5/13
sin u= 5/13
cos u= 12/13
tan u= 5/12
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proof: Draw seg OD.
∠ACB = 90° angle inscribed in semicircle
∠ACB = 45° CD is the bisector of ∠C
m(arc DB) = 2∠ACB = 90° inscribed angle theorem
∠DOB = 90° definition of measure of an arc (I)
seg OA ≅ seg OB Radii of the circle (II)
∴ line OD is prependicular bisector of seg AB From (I) and (II)
∴ seg AD ≅ seg BD
I hope it will help you Ankit
have a nice day
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