SOLve Any TWO Question Of the following
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Answers
1)Construct triangle ABC such that angleB =100 Construct triangle ABC such that angleB =100
=Steps of construction:
i. Construct ∆ABC of the given measurement.
ii. Draw the bisectors of ∠B and ∠C. Let these bisectors intersect at point I.
iii. Draw a perpendicular IM on side BC. Point M is the foot of the perpendicular.
iv. With I as centre and IM as radius, draw a circle which touches all the three sides of the triangle
2)The equation of the given line is 3x − y = 0.
3x − y = 0
⇒ y = 3x
Putting x = 0 in (1), we get
y = 3 × 0 = 0
Putting x = 1 in (1), we get
y = 3 × 1 = 3
Putting x = −1 in (1), we get
y = 3 × (−1) = −3
Putting x = 2 in (1), we get
y = 3 × 2 = 6
These values can be represented in the table in the form of ordered pairs as follows:
(x , y)
(0 , 0)
(1 , 3)
(-1 , -3)
(2 , 6)
4)
ABCD is a parallelogram, diagonals AC and BD intersect at O.
In triangles AOD and COB,
DAO = BCO (alternate interior angles)
AD = CB.
ADO = CBO (alternate interior angles)
AOD COB (ASA)
Hence, AO = CO and OD = OB (c.p.c.t)
Thus, the diagonals of a parallelogram bisect each other.
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