Math, asked by lapcom2019, 7 months ago

solve as soon as possible​

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Answers

Answered by 07armyjam
2

i) here,

let the angle opposite to x be 'y',

then,

y+123=180°[linear pair]

or,y=180°-123°

    y=57°

now,

x+y+56°=180°[sum of all angles of a triangle]

or,x+57°+56°=180°

or,x+113°=180°

or,x=180°-113°

   x=67°  ans

ii)here,

45°+68°+(3x+16)°=180°[sum of all angles of triangle]

or,113°+3x+16°=180°

or,129°+3x=180°

or,3x=180-129

or,x=51/3

    x=17

iii)here,

25°+x+30°=180°[sum of all angles of triangle]

or,55°+x=180°

or,x=180°-55°

    x=125°

iv)here,

2x+7°=45°[base angles of a isosceles triangle]

or,2x=45°-7°

   x=38°

HOPE IT HELPED

and i don't know how to do v no. so i didn't do it ,sorry

   

Answered by nareshsaini77117
0

i) here,

let the angle opposite to x be 'y',

then,

y+123=180°[linear pair]

or,y=180°-123°

    y=57°

now,

x+y+56°=180°[sum of all angles of a triangle]

or,x+57°+56°=180°

or,x+113°=180°

or,x=180°-113°

   x=67°  ans

ii)here,

45°+68°+(3x+16)°=180°[sum of all angles of triangle]

or,113°+3x+16°=180°

or,129°+3x=180°

or,3x=180-129

or,x=51/3

    x=17

iii)here,

25°+x+30°=180°[sum of all angles of triangle]

or,55°+x=180°

or,x=180°-55°

    x=125°

iv)here,

2x+7°=45°[base angles of a isosceles triangle]

or,2x=45°-7°

   x=38°

HOPE IT HELPED

and i don't know how to do v no. so i didn't do it ,sorry

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