Question

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Answer 1

Answer:-

Let x be compression in the spring when the bar m2 is about to shift. Therefore at this moment spring force on m2 is equal to the limiting friction between the bar m2 and horizontal floor. Hence

k x = k m2 g ( where k is spring const ) -------- (1)

from work energy theorem:-

A = ∆T = 0 for minimum force

so fx - 1/ 2 kx^2 - kmgx = 0 -------- (2)

from (1) and (2)

F = kg ( m1 + m2 / 2 )

hope it will help you ....