Question

solve asap but accurately with solution!
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First amd correct answer with solution will be immediately marked as BRAINLIEST​

Answer 1

Answer:

here is your answer

Step-by-step explanation:

Suppose that one man alone can finish the work in x days and one boy alone can finish it in y days. Then,

One man's one day's work = x1

One boy's one day's work = y1

∴ Eight men's one day's work = x8

12 boy's one day's work = y12

Since 8 men and 12 boys can finish the work in 10 days

10( x8+y12)= 1

x 80+y120 = ........1

Again, 6 men and 8 boys can finish the work in 14 days.

∴14( x6+y8)=1

x84 + y112 = 1 ...........2

Putting the x is 1

and y= y1

=v in equations (i) and (ii), we get

80u+120v−1=0

84u+112v−1=0

By using cross-multiplication method, we have

−120+112

u

=

−80+8r

=80×112−120×84

−8 u = -4 v =1120

⇒u= -1120 -8

= 140

and v= -1120 -4

=280

Now, u= 140

⇒ x1 = 140

⇒x=140

and, v= 280

⇒ y1 = 280

⇒y=280.

Thus, one man alone can finish the work in 140 days and one boy alone can finish the work in 280 days