Question

solve: ax + b^2 = a^2 - bx​

Answer 1

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• Solve for x.

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$ax + {b}^{2} = {a}^{2} - bx$

$\implies ax + bx = {a}^{2} - {b}^{2}$

$\implies x(a + b)= (a + b)(a - b)$

$\implies x= \frac{ \cancel{(a + b)}(a - b)}{ \cancel{(a + b)}}$

$\implies x = (a - b)$

$\star\:\:\:\bf\large\underline\blue{Answer:-}$

• $x = (a - b)$