Question

solve: ax-by=1
bx-ay=1

Answer 1

hope it's helpful and write also...

Answer 2

Hey Friend ,

ax - by = 1 -- equation (1)
bx - ay = 1 ---equation (2)
----> ax=1+by

----> x=(1+by)/a

Put above value in equation (2)
b(1+by)/a - ay = 1

b+b^2y-a^2y=a
(b^2-a^2)y=a-b
----> y= (a-b)/(b+a)(b-a)
----> y= -1/(a+b) is the answer

And putting y in given equation ,
ax-b[-1/(a+b)]=1

----> ax+[b/(a+b)]=1
----> ax = 1-[b/(a+b)] = a/(a+b)

----> x = 1/(a+b) is the answer

Let me know if any step is unclear