solve: ax+ by=a-b, bx-ay=a+b
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Answered by
26
ax+by= a-b
bx-ay= a+b
a×(ax+by= a-b)
b×(bx-ay=a+b)
a^2x+ aby=a^2-ab
b^2x- aby= ab+b^2
+
_________________
(a^2+b^2)x =a^2-ab+ab +b^2
a^2+b^2
=>x= ________ = 1
a^2+b^2
=>a×1+ by= a-b
=>by=a-b-a
=>by=-b
=>y=-b/b=-1
bx-ay= a+b
a×(ax+by= a-b)
b×(bx-ay=a+b)
a^2x+ aby=a^2-ab
b^2x- aby= ab+b^2
+
_________________
(a^2+b^2)x =a^2-ab+ab +b^2
a^2+b^2
=>x= ________ = 1
a^2+b^2
=>a×1+ by= a-b
=>by=a-b-a
=>by=-b
=>y=-b/b=-1
Answered by
10
ax+by= a-b
bx-ay= a+b
a×(ax+by= a-b)
b×(bx-ay=a+b)
a^2x+ aby=a^2-ab
+b^2x- aby= ab+b^2
_________________
(a^2+b^2)x =a^2-ab+ab +b^2
a^2+b^2
=>x = 1
a^2+b^2
a×1+ by= a-b
by=a-b-a
by=-b
y=-b/b=-1
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