Solve , b^2 + 9b= 400 . Find b
please tell me the answer
# answer needed with explanation
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b² + 9b –400 =0
by the methods of spilliting the middle term we have
b² +25b –16b –400
taking common we have
b(b+25) –16(b + 25)
by taking common (b+25)
(b+25). (b–16)
is the answer
explaination
now we have to divide the middle term into two parts so that the sum of both is equals to 9b end product of both is equals –400
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