Math, asked by blastroidd, 4 days ago

solve b square sin square c + b square cos square c

Answers

Answered by BhavyaSingh1098

1

b²sin²c + b²cos²c

b² + b² / sin²(0)+cos²(0) = 1

2b²

Please mark me as brainliest

Answered by Shilho123

0

Answer

b²sin²c + b²cos²c

b² + b² / sin²(0)+cos²(0) = 1

2b²

Hope it helps you

Please mark me as brainiest

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