Question

Solve B2.. Ans is 287.5 j​

Answer 1

Answer:

See below and refer diagram image attached with the answer.

Explanation:

We find the area of triangle ABH and name it as A1,

$A_1 = A( \Delta ABH ) = \frac{10 \times 10}{2} = 50 \ J$

Next, we find the area of rectangle HBCG and name it as A2,

$A_2 = A( HBCG ) = 20 \times 10 = 200 \ J$

Now, we find the area of triangle GFE and name it A3,

$A_3 = A( \Delta GFE ) = \frac{5 \times 5}{2} = 12.5 \ J$

Now, we find the area of square FCDE and name it A4,

$A_4 = A( FCDE ) = 5^2 = 25 \ J$

Now, we add A1, A2, A3 and A4,

$A_1 + A_2 + A_3 + A_4 = 50 + 200 + 12.5 + 25 = 275 + 12.5 = 287.5 \ J$

Which matches your answer.