solve both.....☺️....................
Attachments:
Answers
Answered by
0
Diagonal of Square = 2r
let Side of Square = k
then 2k^2 = 4r^2
k^2 = 2r^2
Area of square = 2r^2
Area of circle = πr^2
p = (πr^2 - 2r^2)/πr^2
p = π-2/π
let Side of Square = k
then 2k^2 = 4r^2
k^2 = 2r^2
Area of square = 2r^2
Area of circle = πr^2
p = (πr^2 - 2r^2)/πr^2
p = π-2/π
Similar questions