Solve both of the questions
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1.
Let the original amount that Dinesh had be X.
Then, Amount spent on grocery = X/2
Also, Amount spent on medicine = X/3
And, Money He had left = 200
Now, According to the question
X/2 + X/3 + 200 = X
=> X- X/2- X/3 = 200
=> (6X - 3X - 2X)/6 = 200
=> X = 200 ×6 = 1200
Hence, Original Amount = Rs. 1200
2.
Let the width of the rectangular plot be X.
Then, length = 2X
Now,
Perimeter = 2(l+b)
=> 120 = 2{2x + x}
=> X = 20
So, Length = 2X = 2× 20 = 40m
And, Breadth = 20m
So, Size or Area = l×b = 40 ×20 = 800m^2.
Let the original amount that Dinesh had be X.
Then, Amount spent on grocery = X/2
Also, Amount spent on medicine = X/3
And, Money He had left = 200
Now, According to the question
X/2 + X/3 + 200 = X
=> X- X/2- X/3 = 200
=> (6X - 3X - 2X)/6 = 200
=> X = 200 ×6 = 1200
Hence, Original Amount = Rs. 1200
2.
Let the width of the rectangular plot be X.
Then, length = 2X
Now,
Perimeter = 2(l+b)
=> 120 = 2{2x + x}
=> X = 20
So, Length = 2X = 2× 20 = 40m
And, Breadth = 20m
So, Size or Area = l×b = 40 ×20 = 800m^2.
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2
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