Question

solve both of these 1 and 2

Answer 1

1) 125^1/3

= (5³)^-1/3
=5^-3/3
= 5^-1
= $\frac{1}{5}$

Binomial of degree 35
a) $x^{35} + yz$
b) $x^{10}y^{10}z^{15} + xz.$

Monomial of degree 100
1 ) ${x}^{74} {y}^{20} {z}^{6}$
2) ${y}^{100}$

Answer 2

$\sqrt[3]{125} {?}^{ - 1} \\ {5}^{ - 1 } \\ 1 \div 5$
=1/5
2nd =x-y^35 and x^100