Question

Solve both question step by step
don't give spam solution ☺☺☺☺☺

Answer 1

Answer to 4th and 5th Question.
If this helps please mark the answer as brainliest.

Answer 2

Q.4.

$\mathbb{ANSWER : }$

Let, population a year ago be $\bf{P}$
Present population of town = 22000
Rate of increase in population annually = 10%

$P(1 + \frac{10}{100} ) = 22000 \\ \\ = > P( \frac{11}{10} ) = 22000 \\ \\ = > P = 22000 \times \frac{10}{11} \\ \\ = > P = 20000$

$\underline{\bf{Hence, \:the\: population\: of the\\\:town \:a \:year \:ago\: was \:20000}}$

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

Q.5.

$\mathbb{ANSWER : }$

Let, Manoj's income be Rs. 100

20% was increased in his income,

= 20% of 100 + 100

= 20+100 = Rs. 120

20% was decreased in his income,

= 120 - 20% of 120

= 120 - 24 = Rs. 96

$\bf{Net\: decrease = 100 - 96 = Rs. 4}$

$\% = \frac{4}{100} \times 100 = 4\%$

$\underline{\bf{Hence, \:the\: total\: percentage \: \:change\: in \:Manoj's \:income }}$ = 4%