Solve both questions......
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on rationalising denominator
(5+√3/7-4√3)(7+4√3/7+4√3)
(5+√3)(7+4√3)/(7-4√3)(7+4√3)
(35+20√3+7√3+12)/(7^2-(4√3)^2)
(47+27√3)/(49-48)
47+27√3 = 47a+√3b
on comparing L.H.S and R.H.S
a=1 and b=27
(5+√3/7-4√3)(7+4√3/7+4√3)
(5+√3)(7+4√3)/(7-4√3)(7+4√3)
(35+20√3+7√3+12)/(7^2-(4√3)^2)
(47+27√3)/(49-48)
47+27√3 = 47a+√3b
on comparing L.H.S and R.H.S
a=1 and b=27
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