Question

Solve both sums including statements

Answer 1

Hope this is helpful

Answer 2

♠️The first sum :-

Given that the sum of three consecutive natural numbers is 48.
So,
Let the first number be x
Then the consecutive numbers will be :-
x+2, x+4.

So,
The three numbers are
$x$
$x + 2$
$x + 4$
Now

Their sum is given 48
So,
$x + x + 2 + x + 4 = 48 \\ \\ 3x + 6 = 48 \\ \\ 3x = 48 - 6 = 42 \\ \\ x = \frac{42}{3} = 14$

Now

The greatest number is equal to x +4
So
If x = 14 (solved)
So, x+4 will be
$x + 4 = 14 + 4 = 18$

♠️Sum number 2 :-

The total amount withdrawn is rs100000

Now,
The cashier gave the denominations is rs 500 and rs 1000

The total number of notes were 175

Now,

Let the number of 500 notes be x and number of rs 1000 notes be y
So,
As per question

$x + y = 175$
Also,
We know that
$500x + 1000y = 100000$
Because we know that the total amount of money which was withdrawn was 1 lakh
So
Simplifying the second equation

$500x + 1000y = 100000 \\ \\ 500(x + 2y) = 100000 \\ \\ x + 2y = \frac{100000}{500} = 200$
Now

We got two equation s

$x + y = 175 \\ x + 2y = 200$
Subtracting the two equations we get :-

$x + 2y = 200 \\ x + y = 175 \\ - \: \: \: - \: \: - \\ = = = = = = = \\ y = 25$
So,
Obtaining x
X = 175 - Y = 175 - 25 = 150

SO,
The 500 notes are 150 in number and 1000 notes are 25 in number.