solve both the question 10 , 11
Attachments:
Answers
Answered by
0
Answer:
Question 10 : -
(1) ∠QPR = 180° - ∠PRQ −∠RQP
⇒ ∠QPR = 180° − 90° − 65° = 25°
(2) ∠QPM = 180° - ∠PMQ − ∠PQM
⇒ ∠QPM = 180° − 90° − 50° = 40°
(3) ∠PSR = 180° −∠PQR
⇒ 180° − 65°
⇒ 115°
∠PRS = 180° -∠SPR − ∠PSR
∠PRS= 180° − 40° − 11° = 25°
barjeshsarathe:
wrong
typo in the last line
question no. 11 bataoo
80 and 80
O double ho jayega 40 ka using theorem
and side wala bhi 80 as angles subtended from the same arc are equal
ek baar acche se theorem smj lo na bhai YT se
Answered by
0
Answer:
try to understand the theorems and you will able to easily solve them....and answer given above is wrong if prs is 15 then it wont satisfy the triangle as 115+40+15 is 170 not 180
Attachments:
if u already knew the answer y asking on brainly ?
hope its correct now
well I didn't ask.... you need an eye specialist JK I didnt post but someone else did
ya my bad i thought both the users are same
Similar questions