Question

solve bx/a-ay/b+a+b=0 and bx-ay+2ab=0​

Answer 1

Answer:

Hope my answer helps

Step-by-step explanation:

Elimination method.

⇒ (b2x - a2y  + a2b +ab 2) / ab = 0 and (bx) - (ay) + 2ab = 0

⇒ (b2x - a2y  + a2b +ab 2) = 0 ---------→(1)

⇒ (bx) - (ay) + 2ab = 0    ---------→(2)

Multiply equation (2) by b

(b2x) - (aby) + 2ab2 = 0            ---------→(3)

Substract (3) from (1)

⇒ - a2y + aby + a2b +ab 2 -2ab2  = 0

⇒ y(ab – a2) = ab2-a2b

⇒ ya(b – a) = ab(b-a)

⇒ y = b

sub y =b in equ (2)

we get (bx) - (ab) + 2ab = 0

⇒ b(x + a) =0

⇒ x+a = 0

⇒ x = -a. and y =b.